Calculate how many grams of O2(g) can be produced from heating 37.0 grams of KClO3(s).
Formula: 2KClO3 = 2KCl + 3O2
determine the moles of KClO3 (mass/molemass)
then multiply that by 3/2, that is the moles of oxygen you get.
Then, convert those moles O2 to grams O2
To calculate the number of grams of O2(g) produced from heating 37.0 grams of KClO3(s), we will follow these steps:
Step 1: Determine the molar mass of KClO3.
The molar mass of K (potassium) is 39.10 g/mol.
The molar mass of Cl (chlorine) is 35.45 g/mol.
The molar mass of O (oxygen) is 16.00 g/mol.
To calculate the molar mass of KClO3, sum the molar masses of each element:
Molar mass of KClO3 = (39.10 g/mol × 2) + 35.45 g/mol + (16.00 g/mol × 3) = 122.55 g/mol.
Step 2: Calculate the number of moles of KClO3.
To calculate the number of moles, divide the given mass by the molar mass:
Number of moles of KClO3 = 37.0 g ÷ 122.55 g/mol = 0.302 moles.
Step 3: Determine the stoichiometry.
From the balanced equation, we see that 2 moles of KClO3 produce 3 moles of O2. Therefore, the molar ratio is 3 moles of O2 for every 2 moles of KClO3.
Step 4: Calculate the number of moles of O2 produced.
Using the mole ratio from step 3, we can calculate the number of moles of O2 produced:
Number of moles of O2 = 0.302 moles KClO3 × (3 moles O2 / 2 moles KClO3) = 0.453 moles O2.
Step 5: Convert moles of O2 to grams.
To convert moles of O2 to grams, multiply the number of moles by the molar mass of O2:
Mass of O2 = 0.453 moles × 32.00 g/mol = 14.496 grams of O2.
Therefore, 37.0 grams of KClO3 can produce 14.496 grams of O2(g) when heated.