Calculate how much K3Fe(CN)6 [MW: 329.24] you would need to weigh out to make a 1x10-3 M solution dissolved in 0.2 M NaNO3 in a 100 ml volumetric

so far i have worked out that 0.329 g will give me the 1x10-3 M, but im confused when it is dissolved into the NaNO3.

mols K3Fe(CN)6 = M x L = 1E-3M x 0.100 L = ?

Then grams = mols x molar mass = 1E-4 x 329.24 = 0.032924 g
The NaNO3 provides only the 100 mL volume.
In the end you will have a solution that is 1E-3 M in KeFe(CN)6 and also 0.2 M in NaNO3

NERD Alert!!!

To calculate the amount of K3Fe(CN)6 needed to make a 1x10-3 M solution, we need to consider the molarity and volume of the final solution.

First, let's calculate the number of moles of K3Fe(CN)6 required to achieve a 1x10-3 M concentration in a 100 ml solution.

Molarity (M) is defined as moles of solute per liter of solution. Therefore, we can use the formula:

Molarity = Moles of solute / Volume of solution (in liters)

Given:
Molarity = 1x10-3 M
Volume of solution = 100 ml = 0.1 L

Rearranging the formula, we can solve for the moles of solute:

Moles of solute = Molarity x Volume of solution

Moles of solute = (1x10-3 M) x (0.1 L)
Moles of solute = 1x10-4 moles

Now, to find the mass of K3Fe(CN)6 required, we'll used the molecular weight (MW).

Mass = Moles of solute x Molecular weight

Given:
Molecular weight (MW) = 329.24 g/mol
Moles of solute = 1x10-4 moles

Mass = (1x10-4 moles) x (329.24 g/mol)
Mass = 0.032924 g

Therefore, you would need to weigh out approximately 0.032924 grams of K3Fe(CN)6 to make a 1x10-3 M solution.

Now, taking into consideration that the solution is dissolved in a 0.2 M NaNO3 solution, you'll need to consider the additional volume of the NaNO3.

The NaNO3 concentration is given as 0.2 M, meaning there are 0.2 moles of NaNO3 per liter of solution. Since the final volume is 100 ml (0.1 L), we can calculate the moles of NaNO3:

Moles of NaNO3 = Molarity x Volume of solution

Moles of NaNO3 = (0.2 M) x (0.1 L)
Moles of NaNO3 = 0.02 moles

We can then convert moles of NaNO3 to grams using its molecular weight (MW = 85.00 g/mol):

Mass of NaNO3 = Moles of NaNO3 x Molecular weight

Mass of NaNO3 = (0.02 moles) x (85.00 g/mol)
Mass of NaNO3 = 1.7 g

Therefore, when you dissolve the 0.032924 grams of K3Fe(CN)6 in the 0.2 M NaNO3 solution, you would have a total mass of 1.7 grams.

Please note that this calculation assumes the complete dissolution of both substances and no interaction between them. The actual process may require slight adjustments based on the behavior of the compounds.