Assume that the batter did not continue to swing the bat after the collision (no energy was added to the system). How fast was the bat moving after the collision? The ball mass .145kg, the bats mass is 1.1kg. And the balls velocity is 44.7m/s and the bats velocity prior to hitting the ball is 43m/s.

To determine the final velocity of the bat after the collision, we can use the principle of conservation of momentum. According to the principle, the total momentum before the collision should be equal to the total momentum after the collision.

The momentum of an object is defined as the product of its mass and velocity. Mathematically, momentum (p) is given by:

p = (mass) * (velocity)

Let's denote the ball's mass as m1 (0.145 kg), ball's velocity as v1 (44.7 m/s), bat's mass as m2 (1.1 kg), and bat's velocity before hitting the ball as v2 (43 m/s).

The initial momentum of the system (before the collision) is the sum of the momenta of the ball and the bat:

Initial momentum = (m1 * v1) + (m2 * v2)

Since the batter didn't continue to swing the bat after the collision, we can assume that no external force was applied, and thus, the only interaction occurred between the ball and the bat. In this case, the momentum after the collision is shared between the ball and the bat equally.

Let's denote the final velocity of the ball after the collision as v1f and the final velocity of the bat after the collision as v2f.

The total momentum after the collision is the sum of the momenta of the ball and the bat:

Total momentum after collision = (m1 * v1f) + (m2 * v2f)

Since we assume that no energy was added to the system and the bat did not continue to swing, the total momentum before the collision is equal to the total momentum after the collision:

(m1 * v1) + (m2 * v2) = (m1 * v1f) + (m2 * v2f)

Now we can plug in the given values:

(0.145 kg * 44.7 m/s) + (1.1 kg * 43 m/s) = (0.145 kg * v1f) + (1.1 kg * v2f)

Simplifying the equation will give us the final velocity of the bat after the collision (v2f):

0.145 kg * 44.7 m/s + 1.1 kg * 43 m/s = 0.145 kg * v1f + 1.1 kg * v2f

6.4715 kg·m/s + 47.3 kg·m/s = 0.145 kg * v1f + 1.1 kg * v2f

53.7715 kg·m/s = 0.145 kg * v1f + 1.1 kg * v2f

Since the momentum of the system was conserved, we can solve this equation to find the final velocity of the bat after the collision (v2f).