A material has an optical purity of 50%. How much of each of the enantiomers is present.

The R enantiomer of a material has rotation of +35. what is the rotation of the S enantiomers.

I only need help with the second question.

Thanks!

If the specific rotation of R is +35 then the rotation of S must be -35.

To determine the amount of each enantiomer present in a material with optical purity of 50%, we assume that the material consists of equal amounts of both enantiomers. Therefore, in this scenario, the material would contain 50% of the R enantiomer and 50% of the S enantiomer.

Now, to find the rotation of the S enantiomer given that the R enantiomer has a rotation of +35, we need to consider the relationship between the rotations of the two enantiomers. Specifically, enantiomers have equal and opposite optical rotations.

In this case, the R enantiomer has a rotation of +35. Since the S enantiomer is the mirror image of the R enantiomer, it will have the same magnitude of rotation but in the opposite direction. This means the rotation of the S enantiomer would be -35.

To summarize:
- The material has an optical purity of 50%, meaning it consists of equal amounts of the R and S enantiomer.
- The R enantiomer has a rotation of +35.
- The S enantiomer will have the same magnitude of rotation (-35) but in the opposite direction.