1.) (2+4i)/3i= 2.) (1-2i)/2i=
I will do the first, you do the second (2+4i)/i = (2+4i)/i * i/i = (2i + 4i^2)/i^2 = (2i - 4)/-1 = 4 - 2i (remember i^2 = -1)
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