if A 52 card deck of playing cards is shuffled, and one card is dealt from the top of the deck. What is the probability that it is a red ten?
52 cards in a standard deck. 13 Diamonds
13 Hearts all RED.
Then have 13 Spades and 13 Clubs, all BLACK
so 26 red cards total and 26 black cards would it be 26 out of 52 of chosing a red ten?
Very straight-forward
There are 2 red tens, the 10 of hearts, and the 10 of diamonds
so prob(red ten) = 2/52 = 1/26
Your last sentence makes no sense to me.
To determine the probability of drawing a red ten from a shuffled deck of 52 cards, we need to calculate the number of favorable outcomes (red tens) over the total number of possible outcomes (all cards in the deck).
In a standard deck of 52 cards, there are two red tens: the ten of hearts and the ten of diamonds. Therefore, the number of favorable outcomes is 2.
The total number of cards in the deck is 52, so the total number of possible outcomes is 52.
To calculate the probability, divide the number of favorable outcomes by the total number of possible outcomes:
Probability = Number of favorable outcomes / Total number of possible outcomes
Therefore, the probability of drawing a red ten from the top of a shuffled deck is:
Probability = 2 (number of red tens) / 52 (total number of cards)
Simplifying the fraction, we get:
Probability = 1/26
Therefore, the probability of drawing a red ten is 1 out of 26, or approximately 0.0385, which can also be expressed as approximately 3.85%.
To find the probability of drawing a red ten from a shuffled deck of 52 playing cards, you need to determine the number of red tens in the deck and divide it by the total number of cards.
In a standard deck of 52 cards, there are 26 red cards and 52 total cards. However, there are only two red tens in the deck, specifically the ten of hearts and the ten of diamonds.
Therefore, the probability of drawing a red ten would be 2 out of 52, which can be simplified to 1 out of 26.