---This was the previous one---
Substances A, B, and C can all act as oxidizing agents. In solution, A is green, B is yellow, and C is red. In the reactions in which they participate, they are reduced to A-, B-, and C- ions, all of which are colorless. When a solution of C is mixed with one containing B- ions, the color changes from red to yellow.
Which species is oxidized? Which is reduced?
When a solution of C is mixed with one containing A- ions, the color remains red.
Is C a better oxidizing agent than A?
Is C a better oxidizing agent than B?
Arrange A B and C in order of increasing strength as an oxidizing agent.
C + B^- ==> C^- + B
You know B^- us colorless and it turns yellow which is the color of B. So the reaction is as I wrote above.
C gains electrons in going to C^- so it is reduced. B^- loses electrons in going to B. It is oxidized.
C+ A^- ==> stays red which means no reaction.
So we have these reactions.
C + A^- ==> N.R.
C + B^- ==> C^- + B
What is an oxidizing agent? That is the gain of electrons is the substance reduced which makes it the oxidizing agent. So C ==> C^- is the gain of electrons which means those reactions above shows which is the stronger oxidizing agent.
C reacts with B^- which means C is a better oxidizing agent than B.
C does not react with A^- which means that A is a stronger oxidizing agent than C.
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--- New ---
You are given an unknown, colorless, solution that contains one of the following salts: NaA, NaB, NaC. In solution, each salt dissociates completely into the Na+ ion and the anion A-,B-,C-. The Na+ ion is effectively inert. Develop a simple procedure for identifying the salt that is present.
Is this part of the same question? If so you must have some of A, some of B and some of C
Mix A with the three. It will not react with A^- but will with B^- and C^-
Mix B with the three. It will not react with A or B or C.
Mix C with the three and it will not react with A but will with B.
Then make the choices.
This follows the strength as an oxidizing agent of A, C, B.
All information comes from previous answers
To identify the salt present in the unknown, colorless solution (NaA, NaB, or NaC), you can perform the following procedure:
1. Take a small portion of the unknown solution.
2. Add a few drops of a solution containing B- ions to the unknown solution.
3. Observe any color change that occurs.
If the color of the solution changes to yellow, it means that the anion in the unknown solution is B-. This indicates that the salt present is NaB.
If the color of the solution doesn't change, proceed to step 4.
4. Take another small portion of the unknown solution.
5. Add a few drops of a solution containing A- ions to the unknown solution.
6. Observe any color change that occurs.
If the color of the solution changes to green, it means that the anion in the unknown solution is A-. This indicates that the salt present is NaA.
If the color of the solution doesn't change, it means that the anion in the unknown solution is C-. This indicates that the salt present is NaC.
To identify the salt present in the unknown solution, we can use a process called precipitation. This involves reacting the solution with another chemical reagent that will cause a visible reaction with the specific anion present in the salt.
Here's a step-by-step procedure to identify the salt:
1. Start by taking a small portion of the unknown solution and divide it into three test tubes.
2. In the first test tube, add a few drops of a solution containing a known cation that forms an insoluble precipitate with anion A-. Observe the reaction. If a white precipitate forms, it indicates the presence of salt NaA.
3. In the second test tube, add a few drops of a solution containing a known cation that forms an insoluble precipitate with anion B-. Observe the reaction. If a colored precipitate forms, it indicates the presence of salt NaB.
4. In the third test tube, add a few drops of a solution containing a known cation that forms an insoluble precipitate with anion C-. Observe the reaction. If a colored precipitate forms, it indicates the presence of salt NaC.
5. Compare the observations from step 2, 3, and 4 to determine which anion is present in the unknown solution.
By following this procedure, we can easily identify the salt present in the unknown solution by observing the formation of precipitates when reacted with specific cations.