I have a quick question. When I did this I got my derivative but one question is asking when Rearranging this, we get
8y7y' = ???? i don't know
We now have d/ dx [x5 + y8] = 5x4 + 8y7y' = d/ dx [9] = 0.
Solving for y', we conclude that the derivative is
y' = -5x^4/8y^7
To understand how to rearrange the equation 8y7y' = ???, let's break it down.
The original equation is 8y7y' = ???, and you are asked to rearrange it. Rearranging usually means isolating one variable or simplifying the equation to make it easier to solve. In this case, you have an equation involving the derivative of y, which is denoted as y'.
To rearrange this equation, you need to isolate y'. Let's go through the steps:
Step 1: Divide both sides of the equation by 8y7 to isolate y'.
8y7y' / 8y7 = ??? / 8y7
y' = ??? / 8y7
Step 2: Simplify the right side of the equation.
Now, the right side of the equation is still unknown, represented by ???. Without more information or context, it is not possible to determine its exact value.
However, in the given context, the equation 8y7y' = ??? is part of a larger problem where you have to find the derivative of x5 + y8 with respect to x. By taking the derivative of x5 + y8, you found that it is equal to 5x4 + 8y7y'.
Thus, the rearranged equation becomes:
y' = (5x4 + 8y7y') / 8y7
Further simplifications can be made if you have additional information about the variables x and y or if you want to simplify the equation for a specific purpose.