In my problem i need to find the mass of Ag in AgNO3. I have 3.489g of AgNO3. Help please!
Determine the percentage composition from the formula.
PercentAg= atomicmassAg/molmassAgNO3
Then, mass Ag= 3.489 * decimal percent above.
To find the mass of Ag in AgNO3, you first need to calculate the percentage of Ag in AgNO3 using the formula provided.
1. Determine the molar mass of AgNO3:
- The atomic mass of Ag is 107.87 g/mol
- The molar mass of NO3 is 62.00 g/mol (14.01 g/mol for N and 3 * 16.00 g/mol for O)
Adding these together: 107.87 g/mol + 62.00 g/mol = 169.87 g/mol
2. Calculate the percentage composition of Ag in AgNO3:
- Divide the atomic mass of Ag (107.87 g/mol) by the molar mass of AgNO3 (169.87 g/mol)
- Multiply the result by 100 to get the percentage:
Percentage Ag = (107.87 g/mol / 169.87 g/mol) * 100
3. Once you have the percentage of Ag in AgNO3, you can calculate the mass of Ag using the equation:
Mass of Ag = Percentage Ag * 3.489 g
So, to summarize, you need to calculate the percentage of Ag in AgNO3 by dividing the atomic mass of Ag by the molar mass of AgNO3. Then, multiply the percentage by the given mass of AgNO3 (3.489 g) to get the mass of Ag.