Consider the following balanced equation: 2N2H4(g)+N2O4(g)→3N2(g)+4H2O(g) Complete the following table showing the appropriate number of moles of reactants and products. If the number of moles of a reactant is provided, fill in the required amount of the other reactant, as well as the moles of each product formed. If the number of moles of a product is provided, fill in the required amount of each reactant to make that amount of product, as well as the amount of the other product that is made.

Mol N2H4 Mol N2O4 Mol N2 Mol H2O

_____ 8 _____ _____
_____ _____ _____ 14
_____ 4.5 _____ ____
_____ _____ 11.8 _____

How do i do this example please.
Thank you!

What's the problem? It looks just like the one you had earlier. Use the coefficients. They will convert whatever you have into whatever you want.

To solve this example, we need to use the stoichiometry of the balanced chemical equation provided. The coefficients in the balanced equation represent the ratio of moles of each substance.

Let's go step by step to complete the table:

1. For the first row, where the moles of N2O4 are given as 8, we can use the ratio of 2:1 between N2H4 and N2O4 to determine the moles of N2H4. Since the ratio of N2H4:N2O4 is 2:1, we can calculate it as follows:
Moles of N2H4 = (8 moles of N2O4) * (2 moles of N2H4 / 1 mole of N2O4) = 16 moles of N2H4
For the product side, we can use the ratio of 3:1 between N2 and N2O4. Thus,
Moles of N2 = (8 moles of N2O4) * (3 moles of N2 / 1 mole of N2O4) = 24 moles of N2
Now, we can calculate the moles of H2O using the ratio of 4:1 between H2O and N2O4. So,
Moles of H2O = (8 moles of N2O4) * (4 moles of H2O / 1 mole of N2O4) = 32 moles of H2O

2. For the second row, where the moles of H2O are given as 14, we need to work backward to find the moles of reactants. Using the ratio of 4:1 between H2O and N2O4, we can calculate the moles of N2O4:
Moles of N2O4 = (14 moles of H2O) * (1 mole of N2O4 / 4 moles of H2O) = 3.5 moles of N2O4
For the product side, we can use the ratio of 3:1 between N2 and N2O4. Thus,
Moles of N2 = (3.5 moles of N2O4) * (3 moles of N2 / 1 mole of N2O4) = 10.5 moles of N2
Now, we go back to reactants and calculate the moles of N2H4 using the ratio of 2:1 between N2H4 and N2O4. So,
Moles of N2H4 = (3.5 moles of N2O4) * (2 moles of N2H4 / 1 mole of N2O4) = 7 moles of N2H4

3. For the third row, where the moles of N2O4 are given as 4.5, we can use the ratio of 2:1 between N2H4 and N2O4 to determine the moles of N2H4. Thus,
Moles of N2H4 = (4.5 moles of N2O4) * (2 moles of N2H4 / 1 mole of N2O4) = 9 moles of N2H4
For the product side, we can use the ratio of 3:1 between N2 and N2O4. So,
Moles of N2 = (4.5 moles of N2O4) * (3 moles of N2 / 1 mole of N2O4) = 13.5 moles of N2
Now, we can calculate the moles of H2O using the ratio of 4:1 between H2O and N2O4.
Moles of H2O = (4.5 moles of N2O4) * (4 moles of H2O / 1 mole of N2O4) = 18 moles of H2O

4. Finally, for the fourth row, we are given the moles of N2 as 11.8. We need to work backward to find the moles of reactants. Using the ratio of 3:1 between N2 and N2O4, we can calculate the moles of N2O4:
Moles of N2O4 = (11.8 moles of N2) * (1 mole of N2O4 / 3 moles of N2) = 3.93 moles of N2O4
Now, going back to reactants, we will calculate the moles of N2H4 using the ratio of 2:1 between N2H4 and N2O4. So,
Moles of N2H4 = (3.93 moles of N2O4) * (2 moles of N2H4 / 1 mole of N2O4) = 7.86 moles of N2H4
Lastly, we can use the ratio of 4:1 between H2O and N2O4 to determine the moles of H2O:
Moles of H2O = (3.93 moles of N2O4) * (4 moles of H2O / 1 mole of N2O4) = 15.71 moles of H2O

By following these steps, you can fill in the appropriate number of moles for each reactant and product in the given table.