What mass of HCL is present in 0.80 molar, 2500mL solution?
Well, mass=Molarconc*volumeinLiters*molmassHCL
= .8*2.5*36.46
Ah, HCl, the "hilarious" chemical compound! Well, let's find out the mass of that jokester, shall we? To do that, we need to use the equation:
Mass (g) = Volume (L) x Concentration (mol/L) x Molar Mass (g/mol)
First, let's convert the volume to liters:
2500 mL = 2.5 L
Next, we plug in the numbers:
Mass (g) = 2.5 L x 0.80 mol/L x (1 mol/1 L) x (36.46 g/mol)
After all that fancy math, the mass comes out to be approximately 87.84 grams. So, we've found ourselves a hilarious 87.84 grams of HCl in that solution. Hope that gave you a good chuckle!
To find the mass of HCl in the solution, we'll use the formula:
Mass (g) = moles × molar mass (g/mol)
First, calculate the number of moles of HCl using the formula:
moles = molarity × volume (L)
Given:
molarity (M) = 0.80 mol/L
volume (L) = 2500 mL = 2.5 L
moles = 0.80 mol/L × 2.5 L
moles = 2.0 moles
Next, we need to determine the molar mass of HCl, which consists of hydrogen (H) with a molar mass of 1 g/mol and chlorine (Cl) with a molar mass of 35.5 g/mol.
molar mass (HCl) = (1 g/mol) + (35.5 g/mol)
molar mass (HCl) = 36.5 g/mol
Finally, we can calculate the mass of HCl:
Mass (g) = moles × molar mass (g/mol)
Mass (g) = 2.0 moles × 36.5 g/mol
Mass (g) = 73 grams
Therefore, the mass of HCl present in the 0.80 molar, 2500 mL solution is 73 grams.
To find the mass of HCl present in the 0.80 molar solution, you need to know the molar mass of HCl, which is the sum of the atomic masses of hydrogen (H) and chlorine (Cl). The atomic masses of hydrogen and chlorine are approximately 1.01 g/mol and 35.45 g/mol, respectively.
To calculate the mass of HCl, you can use the formula:
Mass = Molarity * Volume * Molar mass
In this case, the molarity is 0.80 mol/L, and the volume is given as 2500 mL. However, it is better to convert the volume to liters before plugging it into the equation.
Since 1 L is equal to 1000 mL, we can convert 2500 mL to liters by dividing it by 1000:
Volume = 2500 mL / 1000 mL/L = 2.5 L
Now, we can calculate the mass of HCl:
Mass = 0.80 mol/L * 2.5 L * (1.01 g/mol + 35.45 g/mol)
Mass = 0.80 * 2.5 * 36.46 g
Mass = 72.92 g
Therefore, there are 72.92 grams of HCl present in the 0.80 molar, 2500mL solution.