Math

The circumference of a sphere was measured to be 74.000 cm with a possible error of 0.50000 cm. Use linear approximation to estimate the maximum error in the calculated surface area.
Estimate the relative error in the calculated surface area. Must be accurate to the fifth decimal place.

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  1. A = 4pi r^2
    dA = 8pi r dr

    Now plug in the numbers. Recall that % error is dA/A * 100

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    posted by Steve

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