A uniform bar 1.100 metres in length and having a cross sectional area of 19.500cm square is subject to a loading of 5050.000 newtons. This load causes an extension to the bar length of 2.610mm.Calculate the stress and strain produced
To calculate the stress, we'll use the formula:
Stress = Force/Area
The given force is 5050.000 newtons, and the area can be found by converting the given area from square centimeters to square meters:
Area = 19.500 cm^2 = (19.500 × 10^-4) m^2
Now we can substitute the values into the formula:
Stress = 5050.000 N / (19.500 × 10^-4) m^2
Now, let's calculate the stress:
Stress = 5050.000 N / (0.00195) m^2
Stress ≈ 2,589,744.68 Pa
To calculate the strain, we'll use the formula:
Strain = (Change in length) / (Original length)
The given change in length is 2.610 mm, and the original length is 1.100 meters. First, we need to convert the given change in length from millimeters to meters:
Change in length = 2.610 mm = (2.610 × 10^-3) m
Now we can substitute the values into the formula:
Strain = (2.610 × 10^-3) m / 1.100 m
Strain ≈ 0.002373
Therefore, the stress produced is approximately 2,589,744.68 Pa, and the strain produced is approximately 0.002373.
stress=Force/Area change area to m^2 first
strain: dL/L=.002610/1.100