Superman throws a boulder of weight 1850N at an adversary on the surface of the earth, where the magnitude of the acceleration due to gravity, g = 9.80m/s2 . What horizontal force must Superman apply to the boulder to give it a horizontal acceleration of 11.6m/s2 ?
F=ma=(1850/g)(11.6)
To determine the horizontal force that Superman must apply to the boulder, we can use Newton's second law of motion, which states that the force applied (F) is equal to the mass of the object (m) multiplied by its acceleration (a):
F = m * a
First, let's find the mass of the boulder by dividing its weight by the acceleration due to gravity:
m = weight / g
m = 1850N / 9.80m/s^2
m ≈ 188.78 kg
Now, we can calculate the horizontal force applied by multiplying the mass by the horizontal acceleration:
F = m * a
F = 188.78 kg * 11.6 m/s^2
F ≈ 2189.25 N
Therefore, Superman needs to apply a horizontal force of approximately 2189.25 Newtons to the boulder.
To find the horizontal force Superman must apply to the boulder, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration. In this case, we need to consider only the horizontal motion of the boulder.
First, let's calculate the mass of the boulder using its weight. Weight is given by the formula weight = mass * acceleration due to gravity. Rearranging the formula, we can calculate the mass as mass = weight / acceleration due to gravity.
Mass = 1850N / 9.8m/s^2 = 188.78 kg (rounded to two decimal places)
Next, we need to find the force required to produce a horizontal acceleration of 11.6m/s^2. Using Newton's second law, force = mass * acceleration.
Force = 188.78 kg * 11.6m/s^2 = 2188.57 N (rounded to two decimal places)
Therefore, Superman must apply a horizontal force of 2188.57 N to the boulder.