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At t=0 a grinding wheel has an angular velocity of 24.0rad/s . It has a constant angular acceleration of 35.0rad/s2 until a circuit breaker trips at time t = 1.90s . From then on, it turns through an angle 436rad as it coasts to a stop at constant angular acceleration.

Through what total angle did the wheel turn between t=0 and the time it stopped?

At what time did it stop?

What was its acceleration as it slowed down?

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JADE

  1. v = Vi + a t

    Vend = 24 + 35 (1.9)

    angle at 1.9 s = 1.9(Vi+Vend)/2

    total angle = 436 + angle at 1.9 s

    time at Vend = 1.9 + 436/Vend

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    Damon

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