A car of mass 550 kg is moving at a speed of 1.5 m/s. A man pushes the car, increasing the speed to 3.2 m/s. How much work did the man do?

A. 3435 J
B. 2816 J
C. 2197 J
D. 4123 J

Work = The change in kinetic energy.

Work = KE2-KE1 = 0.5*m*V2^2-0.5*m*V1^2 = 0.5*550*3.2^2-0.5*550*1.5^2 = 2197 J.

I’d say the man definitely did a lot of work, but unfortunately, I don't have an answer that matches any of the options provided. However, if I were to push the boundaries of physics and imagination, I would say the man did the work of approximately infinity J, because, you know, superheroes do exist!

To find the work done by the man, we need to calculate the change in kinetic energy of the car.

The formula for kinetic energy is:

Kinetic energy = (1/2) * mass * (velocity^2)

Initially, the car has a kinetic energy of:

Initial kinetic energy = (1/2) * 550 kg * (1.5 m/s)^2

Finally, the car has a kinetic energy of:

Final kinetic energy = (1/2) * 550 kg * (3.2 m/s)^2

The change in kinetic energy is:

Change in kinetic energy = Final kinetic energy - Initial kinetic energy

Now, let's calculate the values:

Initial kinetic energy = (1/2) * 550 kg * (1.5 m/s)^2 = 618.75 J

Final kinetic energy = (1/2) * 550 kg * (3.2 m/s)^2 = 2816 J

Change in kinetic energy = 2816 J - 618.75 J = 2197.25 J

Therefore, the work done by the man is approximately 2197 J.

The correct answer is C. 2197 J.

To calculate the work done by the man, we need to use the work-energy principle, which states that the work done on an object is equal to the change in its kinetic energy. The formula for work is given by:

Work = ΔKE = KE2 - KE1

Where:
ΔKE = Change in kinetic energy
KE2 = Final kinetic energy
KE1 = Initial kinetic energy

To calculate the kinetic energy, we need to use the formula:

Kinetic Energy = (1/2) * mass * velocity^2

Given:
Mass of the car = 550 kg
Initial velocity = 1.5 m/s
Final velocity = 3.2 m/s

Now, let's calculate the initial kinetic energy:

KE1 = (1/2) * mass * initial velocity^2
KE1 = (1/2) * 550 kg * (1.5 m/s)^2

KE1 = 618.75 J

Next, let's calculate the final kinetic energy:

KE2 = (1/2) * mass * final velocity^2
KE2 = (1/2) * 550 kg * (3.2 m/s)^2

KE2 = 2816 J

Now, we can calculate the work done by the man:

Work = ΔKE = KE2 - KE1
Work = 2816 J - 618.75 J
Work = 2197.25 J

Therefore, the work done by the man is approximately 2197 J.

Therefore, the correct answer is C. 2197 J.