If we take 2.2 grams of CO2, 6.02 X 1021 atomes of nitrogen and 0.03 gram atoms of sulphar , then the molar ratio of C, N, and O is .
answer is 5:1 :3
how to solve it help please , thanks
Sorry but I made an error above in the conversions and the 5:1:3 IS right after all.
mols CO2 = g/molar mass = 2.2/44 = 0.05. I convert to grams C which isn't right. mols C is the same as mols CO2; therefore, we have
mols C = 0.05
mols N = 0.01
mols O = 0.03
and the ratio is C5NO3
If 0.03 gram atoms of sulfur is given then why ratio of oxygen is asked.....so basicaly there is error in question ratio of Sulfur should be asked instead of Oxygen so
Moles of C=0.05
Moles of N=6.02x10^21/6.02x10^23=0.01
Moles of S=0.03 (1gram atoms = 1mole)
So Ratio is 5:1:3
How can we find moles of oxygen? Plz answer: DrBob222 , Shahab Mirza
It's already given
How did u calculate the moles of sulphur .. plz help!
How to calculate moles for O by this data? Please answer it.
To solve this problem, we need to determine the molar ratio of carbon (C), nitrogen (N), and oxygen (O) in the given compounds. Here's how you can calculate it step by step:
1. Convert the given masses of CO2 and sulfur to moles:
- Molar mass of CO2 = 12.01 g/mol (molar mass of carbon) + 2 * 16.00 g/mol (molar mass of oxygen) = 44.01 g/mol
- Moles of CO2 = mass of CO2 (given: 2.2 g) / molar mass of CO2 = 2.2 g / 44.01 g/mol = 0.05 mol
- Molar mass of sulfur (S) = 32.06 g/mol
- Moles of sulfur = mass of sulfur (given: 0.03 gram atoms) * 1 mol = 0.03 * (Avogadro's number) mol (Since 1 gram atom = 1 mol)
Note: Avogadro's number is 6.02 x 10^23 atoms/mol.
2. Convert the given number of nitrogen atoms to moles:
- Moles of nitrogen (N) = number of nitrogen atoms (given: 6.02 x 10^21 atoms) / Avogadro's number
3. Determine the molar ratio of C, N, and O:
- The molar ratio is the ratio between the number of moles or atoms. Therefore, we need to compare the number of moles of C, N, and O.
- From the balanced chemical formula of CO2, we know that for every 1 mole of CO2, there is 1 mole of C and 2 moles of O.
- So, the molar ratio of C to CO2 is 1:1 (since 1 mole of CO2 contains 1 mole of C).
- The molar ratio of O to CO2 is 2:1 (since 1 mole of CO2 contains 2 moles of O).
- Similarly, determine the molar ratio of N to the number of moles of N determined above.
4. Simplify the molar ratio:
- Simplify the molar ratio by dividing the moles of each element by the lowest number of moles you obtained from step 3.
- In this case, the lowest number of moles is 0.05 (the moles of CO2), so divide the moles of C, N, and O by 0.05.
- Molar ratio of C:N:O = (moles of C / 0.05) : (moles of N / 0.05) : (moles of O / 0.05)
- Calculate the moles of C, N, and O by multiplying the number of atoms or moles by the respective ratio you got from step 3.
After calculating the molar ratios, you should obtain the answer of 5:1:3 as mentioned in the question.
@DrBob222 , thanks for reply, thanks sir
@DrBob222 , Thanks sir, but I still cant understand , help me out,
see , 2.2g X 12/44 = 0.6 moles of CO2, so how to calculate Moles of N and O ?
2g CO2 x (atomic mass C/molarmass CO2) = approx 0.6 mols C
6.02E21/6.02E23 = 0.01 mols N
0.03 mols O
but that isn't 5:1:3 but more like 60:1:3