How would you make a serial dilution if you have a starting value 100mM of X
The are the values of X show different dilutions.
Volume variables (x) mL
0
1
3
1
10
30
100
We starting out with 100mM of X which would be considered its concentration. In order to describe how to do a serial dilution I need to figure out the dilution factor from the volume variables. She wants us to describe how when starting from 100mM of concentration we can obtain those volumes.
Df1= 100ml/30mL = 3.333
Df2= 30mL/ 10= 3
Df3= 10mL/3= 3.333
Df4= 3/1 = 3
Df5= 3/1= 3
so I guess she wants us to work our way from the bottom up so I obtained a dilution factor of 3.333 and 3.
to find out the concentration I have the formula
C= C1/Dfactor
C= 100mM/ 3.333= 30.03mM
how would we describe doing this dilution. From the 30.0mM concentration we add 3.3333 mol per liter. As you see I am still confused. I have no way of asking her for explaination, so If any help could be proivded I would appreciate it.
To perform a serial dilution starting with a 100mM concentration of X, you will need to follow these steps:
1. Prepare a series of tubes or containers labeled with the desired dilution factors (in this case, the volume variables given: 0, 1, 3, 1, 10, 30, and 100 mL).
2. For each dilution, take the appropriate volume of the starting 100mM solution of X and transfer it to the corresponding tube or container.
3. Add a suitable diluent (usually a solvent like water or buffer) to each tube or container in order to achieve the desired final volume.
4. Mix the contents thoroughly to ensure proper dilution.
Here's an example of how to perform the dilution for one of the given values, 30 mL:
- Take 30 mL of the 100mM solution of X and transfer it to a container labeled for a dilution of 30 mL.
- Add a diluent (e.g., water or buffer) to reach a final volume of 30 mL in the container.
- Mix the solution thoroughly to ensure complete dilution.
- The resulting concentration of X in the 30 mL dilution would be equal to the 100mM concentration divided by the dilution factor for that particular dilution. In this case, the dilution factor is 3.333, so the concentration of X in the 30 mL dilution would be approximately 30.03 mM (calculated as 100 mM / 3.333 ā 30.03 mM).
Repeat these steps for each desired dilution volume to obtain the serial dilution series.