"You're creating a standard curve for pyruvate. You need to create a standard with 20 micromoles in a cuvette. How much 100 mM pyruvate would you need?"
My understanding is to solve for VOLUME using the equation:
micromoles = (mM)(volume in ml)
20 micromoles = (100mM)(x)
Solve for x
x = 0.2mL
Am I on the right track?
Yes, you are on the right track. To calculate the volume of the 100 mM pyruvate solution needed to obtain 20 micromoles, you can rearrange the equation:
micromoles = (mM)(volume in ml)
Plugging in the given values:
20 micromoles = (100 mM)(x ml)
To solve for x (the volume in ml), divide both sides of the equation by 100 mM:
x ml = (20 micromoles) / (100 mM)
Now, you need to convert micromoles to moles and milliliters to liters so that the units match:
20 micromoles = 20 x 10^-6 moles
x ml = (20 x 10^-6 moles) / (100 x 10^-3 moles/liter)
Simplifying:
x ml = 0.2 ml
So, you would need 0.2 ml of the 100 mM pyruvate solution to obtain 20 micromoles.