A 55 uL of hexane is injected in a mass spectrometer. how many protons are in the 55 uL injection? (density Hexane= 0.6548 g/mL)
hexane is 86 g/mol
we have 55 uL *.6548 *10^-3 g/uL
= 36*10^-3 g
36*10^-3/86
=4.2 * 10^-4 mol
* 6*10^23 = 2.51*10^20 molecules of hexane
now just add up the protons in a molecule and divide. It is C6H14
C has 6 each and H has 1 each
What about microliter conversion to ml?
It is there
0.6548 g/mL *10^-3 mL/ uL
=.6548 *10^-3 g/uL
To determine the number of protons in the 55 uL injection of hexane, we need to calculate the number of moles of hexane based on its volume and density. Then, using Avogadro's number, we can find the number of molecules of hexane. Finally, we multiply the number of molecules by the number of protons in each hexane molecule.
Here's how you can calculate it step-by-step:
Step 1: Convert the volume of hexane from microliters (uL) to liters (L).
55 uL ÷ 1,000,000 = 0.000055 L
Step 2: Calculate the mass of the hexane injection using its volume and density.
Mass = Volume x Density
Mass = 0.000055 L x 0.6548 g/mL
Mass = 0.00003599 g
Step 3: Convert the mass of hexane from grams to moles using its molar mass.
The molar mass of hexane (C6H14) = 6(12.01 g/mol) + 14(1.01 g/mol) = 86.18 g/mol
Moles = Mass / Molar Mass
Moles = 0.00003599 g / 86.18 g/mol
Moles ≈ 4.179 x 10^-7 mol
Step 4: Calculate the number of molecules of hexane using Avogadro's number.
Avogadro's number (NA) = 6.022 x 10^23 mol^-1
Number of Molecules = Moles x NA
Number of Molecules ≈ 4.179 x 10^-7 mol x 6.022 x 10^23 mol^-1
Number of Molecules ≈ 2.512 x 10^17 molecules
Step 5: Determine the number of protons in each hexane molecule.
Hexane (C6H14) has six carbon atoms, each with 6 protons.
Number of Protons = Number of Carbon atoms x Protons per Carbon
Number of Protons = 6 x 6
Number of Protons = 36 protons
Step 6: Calculate the total number of protons in the hexane injection.
Total Number of Protons = Number of Protons per Molecule x Number of Molecules
Total Number of Protons = 36 protons x 2.512 x 10^17 molecules
Total Number of Protons ≈ 9.043 x 10^18 protons
Therefore, there are approximately 9.043 x 10^18 protons in the 55 uL injection of hexane.