What volume of hydrogen is necessary to react with five liters of nitrogen to produce ammonia? (assume constant temprature and pressure)
Balanced equation- N2 + 3H2= 2NH3
After finding this answer, what volum of ammonia is produced in this reaction?
1. Write the equation. You have that.
2. When working with all gas systems, we can dispense with converting to mols and back again and simply use volumes. Therefore, 1 L N2 will react with 3 L H2 to produce 2 L NH3.
SO, ?L H2 = 5L N2 x (3 mol H2/1 mol N2) = ??
and ?L NH3 = 5L N2 x (2 mol H2/1 mol N2)
= ??
Thank you very much
To find the volume of hydrogen necessary to react with five liters of nitrogen to produce ammonia, we can use the stoichiometry of the balanced equation you provided.
Step 1: Determine the volume of hydrogen needed.
According to the balanced equation: N2 + 3H2 = 2NH3
1 mole of nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia.
Therefore, 1 liter of nitrogen reacts with 3 liters of hydrogen to produce 2 liters of ammonia.
Since we have 5 liters of nitrogen, we can calculate the volume of hydrogen needed:
Volume of hydrogen = 5 liters of nitrogen * (3 liters of hydrogen / 1 liter of nitrogen)
= 15 liters of hydrogen
So, the volume of hydrogen necessary to react with five liters of nitrogen to produce ammonia is 15 liters.
Step 2: Calculate the volume of ammonia produced.
Using the stoichiometry of the balanced equation, we can determine the volume of ammonia produced from the given volume of nitrogen:
Volume of ammonia = 5 liters of nitrogen * (2 liters of ammonia / 1 liter of nitrogen)
= 10 liters of ammonia
Therefore, the volume of ammonia produced in this reaction is 10 liters.