There were 40,000 people at a ball game in Los Angeles. The days receipts were 298,000. How many people paid $12.00 for reserved seats and how many paid $5.00 for general admission?
if there were x reserved seats, then the rest (40000-x) were general admission. So, adding up all the ticket prices, we get
12x + 5(40000-x) = 298000
x = 14000
To determine how many people paid $12.00 for reserved seats and how many paid $5.00 for general admission, we can solve a system of linear equations using the information provided.
Let's denote the number of people who paid $12.00 for reserved seats as "x", and the number of people who paid $5.00 for general admission as "y".
Based on the given information, two equations can be formed:
1) The total number of people who attended the ball game:
x + y = 40,000
2) The total amount of money collected from ticket sales:
12x + 5y = 298,000
Now we can solve the system of equations:
From equation 1:
x = 40,000 - y
Substitute this value of x into equation 2:
12(40,000 - y) + 5y = 298,000
Simplifying the equation:
480,000 - 12y + 5y = 298,000
Combine like terms:
-7y = -182,000
Divide both sides by -7:
y = 26,000
Substituting this value of y back into equation 1:
x + 26,000 = 40,000
Subtracting 26,000 from both sides:
x = 14,000
Therefore, there were 14,000 people who paid $12.00 for reserved seats and 26,000 people who paid $5.00 for general admission at the ball game in Los Angeles.