Quadratic Formula
Using +/- for plus or minus
Using \/ radical sign
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Formula: -b +/- \/b^2-4ac
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Equation:
x^2 - 25 = 0
Books says answer is 5 and -5. I can get the 5. I do not get the -5.
I don't understand.
Didn't you post the formula with a +/- ?
so in your equation x^2 - 25 = 0
a = 1
b = 0
c = -25
so x = (0 ±√(0-4(1)(-25))/2
= ±√100 / 2
= ±10/2
= ±5
of course the easier way would be to write the equation as
x^2 = 25 , then
x = ±√25 = ±5
Yes I did post it with a +/- representing plus or minus the number.
How were you about to show the +- with the minus sign uder the the plus sign?
I looked at the answer you provided I think I can see my error. I was taking 0 for C not the 25. I remember now that C has to be a number without a variable next to it.
To find the solutions of the quadratic equation x^2 - 25 = 0, we can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
For this equation, a = 1, b = 0, and c = -25. Substituting these values into the quadratic formula, we get:
x = (0 ± √(0^2 - 4(1)(-25))) / (2(1))
Simplifying further:
x = ± √(0 - (-100)) / 2
x = ± √100 / 2
x = ± 10 / 2
Simplifying the fraction:
x = ± 5
Therefore, the solutions to the equation x^2 - 25 = 0 are 5 and -5.
To solve the quadratic equation x^2 - 25 = 0 using the quadratic formula, you need to substitute the values of a, b, and c into the formula:
a = coefficient of the quadratic term = 1
b = coefficient of the linear term (with x) = 0
c = constant term = -25
Now, apply the quadratic formula:
x = (-b +/- sqrt(b^2 - 4ac)) / 2a
Plug in the values:
x = (0 +/- sqrt(0^2 - 4(1)(-25))) / 2(1)
= (0 +/- sqrt(0 + 100)) / 2
= (0 +/- sqrt(100)) / 2
= (0 +/- 10) / 2
This gives you the two possible solutions for x:
1. x = (0 + 10) / 2 = 10 / 2 = 5
2. x = (0 - 10) / 2 = -10 / 2 = -5
Therefore, the solutions to the equation x^2 - 25 = 0 are x = 5 and x = -5. Both values satisfy the equation when substituted.