Use a sine function to graph a sound wave with a period of 0.004 of a second and an amplitude of 3 cm. Find the frequency in hertz for this sound wave. (Enter only the number.)
this is just the other problem in reverse. Why not give it a shot? You know that the period of sin(kx) is 2π/k...
Also, period = 1/frequency
Ohh, I see. So, you would multiply 2 x pi x 3 or x 0.004? What is k equal to?
I know we multiply 2pi times coefficient. In this case, I guess I am asking what that is.
Sorry, I just wanted to make my question more clear.
I think I got the answer. I did 1/0.004 and got 250 hz.
C'mon.
If 2π/k = .004, k = 2π/.004 = 500π
To find the frequency in hertz for the sound wave, we can use the formula:
frequency (in hertz) = 1 / period (in seconds)
Given that the period is 0.004 seconds, we can substitute this value into the formula:
frequency = 1 / 0.004
Calculating this expression, we get:
frequency = 250
Therefore, the frequency of the sound wave is 250 Hz.