Write an equation for the line in slope intercept form
Slope:-2 passing through (-2,8)
To write the equation of a line in slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept, we need to find the values for m and b.
Given that the slope (m) is -2 and the line passes through the point (-2, 8), we can use the point-slope form of a line to find the equation. Point-slope form is given by:
y - y1 = m(x - x1)
Substituting the known values into the formula:
y - 8 = -2(x - (-2))
Simplifying the equation:
y - 8 = -2(x + 2)
Distributing -2 to the terms inside the parentheses:
y - 8 = -2x - 4
To write the equation in slope-intercept form, isolate y:
y = -2x - 4 + 8
Simplifying further:
y = -2x + 4
Therefore, the equation of the line in slope-intercept form is y = -2x + 4.
To write the equation of a line in slope-intercept form (y = mx + b), we need to find the slope (m) and the y-intercept (b).
Given:
Slope (m) = -2
Point on the line: (-2,8)
To find the y-intercept (b), we can use the point-slope form of a linear equation:
(y - y₁) = m(x - x₁)
Substituting the values:
(y - 8) = -2(x - (-2))
Now, simplify the equation:
(y - 8) = -2(x + 2)
(y - 8) = -2x - 4
To get the equation in slope-intercept form (y = mx + b), we need to isolate y:
y = -2x - 4 + 8
y = -2x + 4
Therefore, the equation of the line with a slope of -2 passing through the point (-2,8) is y = -2x + 4.
-2(-2)+10 is not 8
use the slope-intercept form:
y-8 = -2(x+2)
y = -2x + 12
I am going to start with the slope-point form. y-y1=m(x-x1)
y-8=-2x-(-2) or y-8=-2x +2
now you add 8 to both sides to get slope intercept form
y=-2x+10