The question is:
ln(x-2e)+ln(x-3e)=2
I know about ln(xy)= ln(x)+ln(y), and I tried it but I can't simplify it without using decimals and I can't use decimals.
so ln(x-2e)+ln(x-3e)=2
ln ( (x-2e)(x-3e) ) = 2
by definition
(x-2e)(x-3e) = e^2
x^2 - 5ex + 6e^2 - e^2 = 0
x^2 - 5ex + 5e^2 = 0
x = (5e ± √(25e^2 - 4(1)(5e^2))/2
= (5e ± √5e^2)/2
= (5e ± e√5)/2
= ( (5±√5)/2 )e