Identify the following chemical equations by type.
1. If an electric discharge produces 800 cm3 of ozone (O3), how many cm3 of oxygen (O2) are required?
3O2(g) ---> 2O3(g)
2. When 75.0 dm3 of O2 react with an excess of glucose (C6H12O2), according to the reaction below, what volume of carbon dioxide will be produced?
6O2(g) + C6H12O6(s) ---> 6H2O(g) + 6CO2(g)
3. If an excess of nitrogen gas reacts with 250 L of hydrogen gas, according to the reaction below, how many L of ammonia will be produced?
N2(g) + 3H2(g) ---> 2NH3(g)
4. How many cm3 of oxygen would be required to react completely with 432 cm3 of hydrogen gas according to the reaction below?
2H2(g) + O2(g) ---> 2H2O(g)
I really need help I cant understand none of this
1.
3O2 --> 2O3
I would call this a synthesis reaction.
2.
oxidation reduction
3.
synthesis
4.
synthesis
Sure! I can help explain the types of chemical equations and how to solve these problems.
1. The given equation is: 3O2(g) ---> 2O3(g)
This is an example of a synthesis reaction, where two or more substances combine to form a single product. In this case, oxygen molecules (O2) combine to form ozone molecules (O3).
To find out how many cm3 of oxygen are required to produce 800 cm3 of ozone, we can set up a ratio using the coefficients from the balanced equation:
3O2 : 2O3
Since the ratio is in terms of moles, we need to convert the volume into moles using the ideal gas equation:
PV = nRT
Once we have the moles of O3, we can use the stoichiometry of the reaction to find the moles of O2 required. Finally, we can convert the moles back into volume using the ideal gas equation.
2. The given equation is: 6O2(g) + C6H12O6(s) ---> 6H2O(g) + 6CO2(g)
This is an example of a combustion reaction, where a substance reacts with oxygen to produce water and carbon dioxide. In this case, glucose (C6H12O6) reacts with oxygen (O2) to form water (H2O) and carbon dioxide (CO2).
To find the volume of carbon dioxide produced when 75.0 dm3 of oxygen reacts, we can set up a ratio using the coefficients from the balanced equation:
6O2 : 6CO2
Similarly, we will need to use the ideal gas equation to convert the volume into moles, and then use the stoichiometry to find the moles of CO2 produced. Finally, we can convert the moles back into volume using the ideal gas equation.
3. The given equation is: N2(g) + 3H2(g) ---> 2NH3(g)
This is an example of a synthesis reaction, where two or more substances combine to form a single product. In this case, nitrogen gas (N2) reacts with hydrogen gas (H2) to form ammonia (NH3).
To find the volume of ammonia produced when 250 L of hydrogen gas reacts, we can set up a ratio using the coefficients from the balanced equation:
3H2 : 2NH3
Again, we will need to use the ideal gas equation to convert the volume into moles, and then use the stoichiometry to find the moles of NH3 produced. Finally, we can convert the moles back into volume using the ideal gas equation.
4. The given equation is: 2H2(g) + O2(g) ---> 2H2O(g)
This is an example of a combustion reaction, where a substance reacts with oxygen to produce water. In this case, hydrogen gas (H2) reacts with oxygen (O2) to form water (H2O).
To find the volume of oxygen required to react completely with 432 cm3 of hydrogen gas, we can set up a ratio using the coefficients from the balanced equation:
2H2 : O2
Once again, we will use the ideal gas equation to convert the volume into moles, and then use the stoichiometry to find the moles of O2 required. Finally, we can convert the moles back into volume using the ideal gas equation.
I hope this helps! If you have any more questions, feel free to ask.