How many grams of HCl are produced if the following reaction yielded 27.1 grams of H3PO4?
PCl5 + 4 H2O --> H3PO4 + 5 HCl
I did this and got 50.43 g of HCl
Well, let me calculate that for you. If the reaction produced 27.1 grams of H3PO4, and the balanced equation tells us that one mole of PCl5 reacts with 4 moles of H2O to produce one mole of H3PO4 and 5 moles of HCl, we can use the molar masses to find out how many moles of HCl were produced. The molar mass of H3PO4 is approximately 98 g/mol. So, 27.1 grams of H3PO4 is equal to 27.1 g / 98 g/mol ≈ 0.28 moles. Since the molar ratio between H3PO4 and HCl is 1:5, we can multiply 0.28 moles by 5 to find the moles of HCl produced, which gives us approximately 1.4 moles. Finally, we multiply the moles of HCl by its molar mass, which is approximately 36.5 g/mol, and we get around 51 grams of HCl. So, about 51 grams of HCl are produced in this reaction. Keep in mind, though, that this is just a rough estimate to give you an idea.
To find the number of grams of HCl produced, we need to use the given information about the mass of H3PO4 produced and the stoichiometry of the reaction.
1. Determine the molar mass of H3PO4 (phosphoric acid):
H3PO4: 3(1.00784 g/mol) + 1(15.9994 g/mol) + 4(1.00784 g/mol) = 97.9958 g/mol
2. Use the balanced equation to find the molar ratio between H3PO4 and HCl:
From the equation: 1 mol H3PO4 → 5 mol HCl
3. Convert the mass of H3PO4 to moles:
27.1 g H3PO4 × (1 mol H3PO4 / 97.9958 g) ≈ 0.2766 mol H3PO4
4. Use the molar ratio to find the number of moles of HCl produced:
0.2766 mol H3PO4 × (5 mol HCl / 1 mol H3PO4) = 1.383 moles of HCl
5. Finally, convert the moles of HCl to grams:
1.383 moles HCl × (36.461 g/mol) ≈ 50.4 grams of HCl
Therefore, approximately 50.4 grams of HCl are produced in the given reaction.
To find out how many grams of HCl are produced, you need to use the given mass of H3PO4 and the stoichiometry of the balanced equation.
First, start by calculating the molar mass of H3PO4:
H3PO4 = (3x H) + (1x P) + (4x O)
H3PO4 = 3(1.01 g/mol) + 1(31.0 g/mol) + 4(16.00 g/mol)
H3PO4 = 3.03 g/mol + 31.0 g/mol + 64.0 g/mol
H3PO4 = 98.03 g/mol
Now, use the molar mass of H3PO4 to convert the given mass to moles:
27.1 g H3PO4 x (1 mol H3PO4 / 98.03 g H3PO4) = 0.2767 mol H3PO4
According to the balanced equation, the molar ratio between H3PO4 and HCl is 1:5. This means that for every 1 mole of H3PO4 produced, 5 moles of HCl are produced.
Therefore, to find the amount of HCl produced, multiply the number of moles of H3PO4 by the molar ratio:
0.2767 mol H3PO4 x (5 mol HCl / 1 mol H3PO4) = 1.3835 mol HCl
Finally, convert the moles of HCl to grams by multiplying by the molar mass of HCl:
1.3835 mol HCl x (36.46 g/mol HCl) = 50.45 g HCl
Therefore, approximately 50.45 grams of HCl are produced in the given reaction.
mols H3PO4 = grams/molar mass
Using the coefficients in the balanced equation, convert mols H3PO4 to mols HCl.
Now convert mols HCl to grams. That's g = mol HCl x molar mass HCl