What is the mass in grams in Br in 7.20 moles of FeBr2?7.20 mol FeBr2x215.65=1552.68=1553 g/m

mols Br in 7.20 mol FeBr2 = 7.2 x 2 = 14.40

Then g Br = mols x atomic mass = 14.40 x 79.9 = ?

To calculate the mass of bromine (Br) in 7.20 moles of FeBr2, you need to use the molar mass of FeBr2 and the conversion factor from moles to grams.

The molar mass of FeBr2 can be calculated by adding up the atomic masses of iron (Fe) and two bromine atoms (Br). Iron has a molar mass of 55.85 g/mol, and bromine has a molar mass of 79.90 g/mol. Therefore, the molar mass of FeBr2 is:

molar mass of FeBr2 = molar mass of Fe + 2 * molar mass of Br
= 55.85 g/mol + 2 * 79.90 g/mol
= 215.65 g/mol

Now, you can use the conversion factor to find the mass of bromine:

mass of Br = moles of FeBr2 × molar mass of FeBr2
= 7.20 mol × 215.65 g/mol
= 1552.68 g

Rounding to three significant figures, the mass of bromine in 7.20 moles of FeBr2 is 1553 g.