A 20kg box rests ona table and a 10kg is placed on top of the 20kg box. Determine the normal force that the table exerts on the 20kg box and the normal force that the 20kg box exerts on the 10kg box.
please help
a. Fn = (m1+m2)*g = (10+20)*9.8 = 294 N.
b. Fn = m1*g = 10 * 9.8 = 98 N.
Okay, let's break it down! So, let's start with the 20kg box. When it's resting on the table, there are two forces acting on it: the weight force pulling it down and the normal force pushing it up from the table.
The weight of the 20kg box can be calculated using the formula weight = mass × gravitational acceleration. In this case, we have weight = 20kg × 9.8m/s² (taking the acceleration due to gravity as 9.8m/s²). So, the weight of the 20kg box is 196N.
Since the box is in equilibrium, the normal force provided by the table is equal in magnitude but opposite in direction to the weight force. Therefore, the normal force exerted by the table on the 20kg box is also 196N.
Now, let's move on to the 10kg box that's placed on top of the 20kg box. Again, there are two forces acting on it: the weight force pulling it down and the normal force pushing it up from the 20kg box.
Using the same method as before, we can find that the weight of the 10kg box is 98N. So, the normal force exerted by the 20kg box on the 10kg box will also be 98N.
To sum it up:
- The normal force that the table exerts on the 20kg box is 196N.
- The normal force that the 20kg box exerts on the 10kg box is 98N.
I hope that clarifies things for you! If you have any more questions, feel free to ask!
To determine the normal force that the table exerts on the 20kg box, we need to consider the weight of the box and the force exerted by the 10kg box on top.
Step 1: Calculate the weight of the 20kg box using the formula: weight = mass x gravitational acceleration.
Weight of the 20kg box = 20kg x 9.8m/s² = 196N.
Step 2: Since the 20kg box is at rest on the table, the normal force exerted by the table will be equal in magnitude and opposite in direction to the weight of the box.
Normal force by the table on the 20kg box = 196N (upwards).
To determine the normal force that the 20kg box exerts on the 10kg box, we need to consider the weight of the 10kg box.
Step 3: Calculate the weight of the 10kg box using the formula: weight = mass x gravitational acceleration.
Weight of the 10kg box = 10kg x 9.8m/s² = 98N.
Step 4: Since the 20kg box is on top and in contact with the 10kg box, the normal force exerted by the 20kg box will balance out the weight of the 10kg box.
Normal force by the 20kg box on the 10kg box = 98N (upwards).
Therefore, the normal force that the table exerts on the 20kg box is 196N (upwards), and the normal force that the 20kg box exerts on the 10kg box is 98N (upwards).
To find the normal force that the table exerts on the 20kg box, we need to consider the gravitational force acting on it.
The weight (W) of an object is given by the equation W = m * g, where m is the mass of the object and g is the acceleration due to gravity (approximately 9.8 m/s^2 on Earth).
In this case, the mass of the 20kg box is 20kg. Thus, its weight is W = 20kg * 9.8 m/s^2 = 196 N (Newtons).
According to Newton's third law of motion, the normal force between two objects is equal in magnitude and opposite in direction. Therefore, the normal force that the table exerts on the 20kg box is also 196 N (since the box is at rest).
Now, to find the normal force that the 20kg box exerts on the 10kg box, we need to consider the weight of the 10kg box and the additional force applied by the 20kg box.
Similarly, the weight of the 10kg box is W = 10kg * 9.8 m/s^2 = 98 N.
Since the 20kg box is sitting on top of the 10kg box, it exerts a downward force on it equal to its weight, which is 196 N.
The normal force that the 20kg box exerts on the 10kg box is the upward force that counteracts the downward force due to gravity and the additional force applied by the 20kg box.
By Newton's third law, the normal force exerted by the 20kg box on the 10kg box is also equal to 196 N (since the 10kg box is at rest and the boxes are in contact).
Therefore, the normal force that the table exerts on the 20kg box is 196 N, and the normal force that the 20kg box exerts on the 10kg box is also 196 N.