P is the product ,n is the consecutive term of geometric progression, s is tje sum of their reciprocal then(S/R)n is equal

a) p
b) p2
c) p3
d) pn

got me. What is R?

To determine the expression (S/R)n, where P is the product and n is the consecutive term of a geometric progression, we need to understand the relationship between the terms of a geometric progression.

In a geometric progression, each term is obtained by multiplying the preceding term by a fixed value called the common ratio (r). Let's assume the first term of the progression is a.

The terms of the geometric progression would be:
a, ar, ar^2, ar^3, ...

The sum of the reciprocals of these terms (S) can be expressed as follows:
S = (1/a) + (1/ar) + (1/ar^2) + (1/ar^3) + ...

To simplify this expression, we can take out a common factor of 1/a:
S = (1/a)(1 + 1/r + 1/r^2 + 1/r^3 + ...)

Now, we need to recall a formula for an infinite geometric series sum:
Sum = a/(1 - r)

By applying this formula to our expression, we have:
S = (1/a)(1 + 1/r + 1/r^2 + 1/r^3 + ...) = (1/a)(1/(1 - 1/r)) = (1/a)(r/(r - 1))

To find the product (P) of the terms in the geometric progression, we multiply all the terms:
P = a * ar * ar^2 * ar^3 * ... = a^(n+1)

Now, let's substitute the values of S and P into the expression (S/R)n:
(S/R)n = [(1/a)(r/(r - 1))] / a^(n+1)

Simplifying further:
(S/R)n = (r/(r - 1))/a^n

Comparing this expression with the answer choices, we can conclude that (S/R)n is equal to pn (option d).