A car traveling in a straight line has a velocity of 3.19 m/s at some instant. After 5.4 s, its velocity is 12 m/s.

What is its average acceleration in this time interval?

a = (V-Vo)/t

V = 12 m/s
Vo = 3.19 m/s.
t = 5.4 s.

To find the average acceleration, we can use the formula:

average acceleration = change in velocity / change in time

First, let's calculate the change in velocity. We are given the initial velocity (3.19 m/s) and the final velocity (12 m/s). Therefore, the change in velocity is:

change in velocity = final velocity - initial velocity
change in velocity = 12 m/s - 3.19 m/s
change in velocity = 8.81 m/s

Next, we need to calculate the change in time. We are given that the time interval is 5.4 s.

change in time = final time - initial time
change in time = 5.4 s - 0 s
change in time = 5.4 s

Now, we can use the formula for average acceleration:

average acceleration = change in velocity / change in time
average acceleration = 8.81 m/s / 5.4 s
average acceleration ≈ 1.63 m/s²

Therefore, the average acceleration of the car in this time interval is approximately 1.63 m/s².