What is the molar concentration of all ions present in a solution prepared by mixing the following? Assume that volumes of the solutions are additive, and neglect H+ and OH- from water.
60.0 mL of 0.25 M KCl and 80.0 mL of 0.85 M NaOH.
To find the molar concentration of all ions in the solution, we need to calculate the number of moles of each ion and then divide by the total volume of the solution.
Step 1: Calculate the number of moles of KCl:
Moles = concentration × volume
Moles of KCl = 0.25 M × 0.060 L = 0.015 moles
Step 2: Calculate the number of moles of NaOH:
Moles of NaOH = 0.85 M × 0.080 L = 0.068 moles
Step 3: Calculate the total moles of ions:
Total moles = Moles of KCl + Moles of NaOH
Total moles = 0.015 moles + 0.068 moles = 0.083 moles
Step 4: Calculate the molar concentration of all ions:
Molar concentration = Total moles / Total volume
Total volume = 60.0 mL + 80.0 mL = 140.0 mL = 0.140 L
Molar concentration = 0.083 moles / 0.140 L ≈ 0.593 M
Therefore, the molar concentration of all ions in the solution is approximately 0.593 M.