When 45 grams of an alloy is dropped into 100.0 grams of water at 25 degrees celcius, the final temperature is 37 degrees celcius. what is the specific heat of the alloy? the alloys Temperature is 100 degrees celsius

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  1. heat lost by alloy + heat gained by water = 0
    heat lost or gained = mass x specific heat x (Tfinal-Tinitial).
    mass alloy x specific heat alloy x (Tfinal-Tinitial) + mass water x specific heat water x (Tfinal-Tinitial) = 0
    You must look up the specific heat of water, the specific heat of the alloy is the only unknown, you know the mass of water and mass of the alloy. I note you spelled Celsius two ways, the correct way is Celsius, not Celcius, probably just a typo. Post your work if you get stuck.

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