if 5.105 gm of KHP (Mwt=204.2)was dissolved in 250 ml,10.70 ml of this solution of KHP was titrated with 10.0 ml of NaOH . Calculate the concentration of NaOH solution
KHP + NaOH ==> NaKP + H2O
mols KHP = grams/molar mass = ?
For titration you took only 10.70 mL of a 250 mL solution so the number of mols titrated was just ?mols x 10.70/250 = x
Looking at the coefficients in the balanced equation and you can see 1 mol KHP = 1 mol NaOH; therefore
mols NaOH = mols KHP from the previous calculation (x that is).
Then M NaOH = mols NaOH/L NaOH. YOu know mols and L, solve for M.
To calculate the concentration of NaOH solution, we need to use the equation:
M1V1 = M2V2
Where:
M1 is the concentration of KHP solution
V1 is the volume of KHP solution used in the titration
M2 is the concentration of NaOH solution
V2 is the volume of NaOH solution used in the titration
First, let's find the concentration of KHP solution:
Step 1: Calculate the number of moles of KHP:
Number of moles = mass / molecular weight
Number of moles = 5.105 gm / 204.2 g/mol
Step 2: Calculate the concentration:
Concentration (M) = moles / volume (in liters)
Since we have 250 ml of KHP solution, we need to convert it to liters:
Volume (liters) = volume (ml) / 1000
Now we can find the concentration of KHP solution.
Next, we can use the given information about the titration of KHP with NaOH:
V1 = 10.70 ml
V2 = 10.0 ml
Now, we can substitute the values into the equation:
M1 * V1 = M2 * V2
Solving for M2:
M2 = (M1 * V1) / V2
By plugging in the values of M1, V1, and V2, we can calculate the concentration of NaOH solution.