The solubility of NaNO3 at 40 oC is 102 g/100 g H2O , what is the minimum amount of water to dissolve NaNO3 ( mass of solvent ) ?
Please
How much NaNO3?
Water required will be
100 g H2O x (g NaNO3/102) = ?
To find the minimum amount of water (mass of solvent) required to dissolve NaNO3, we need to convert the given solubility from a percentage (g/100 g H2O) to a mass ratio.
1. Start by converting the given solubility from a percentage to grams:
Solubility of NaNO3 = 102 g/100 g H2O
2. Determine the mass of NaNO3 needed to achieve this solubility. Since the solubility is given in grams of NaNO3 per 100 grams of water, the same amount of NaNO3 should be dissolved in the minimum amount of water:
Mass of NaNO3 required = 102 g
3. Finally, the minimum amount of water required to dissolve 102 g of NaNO3 is equal to the mass of NaNO3:
Mass of solvent (water) = 102 g
Therefore, the minimum amount of water required to dissolve NaNO3 (mass of solvent) is 102 grams.