A professor orders 250 mL of house coffee at precisely 95°C. She then adds enough milk at 10°C to drop the temperature of the coffee to exactly 90° C.

Calculate the amount of milk (in mL) the professor must add to reach this temperature. Assume that the coffee and milk have the same specific heat capacity: 4.184 J/(g × °C). Assume that they also have the same density: 1.0 g/mL.

  1. 👍 0
  2. 👎 0
  3. 👁 1,409
  1. mass in grams = mL milk
    mass in grams = mL coffee
    heat lost by coffee + heat gained by milk = 0

    [mass coffee x specific heat coffee x (Tfinal-Tinitial)] + [mass milk x specific heat milk x (Tfinal-Tinitial)] = 0
    Substitute the numbers and solve for mass milk in grams which = mL milk.

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  2. 34

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  3. 41.8

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  4. 19.3

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