A person in a kayak starts paddling, and it accelerates from 0 to 0.577 m/s in a distance of 0.565 m. If the combined mass of the person and the kayak is 60.6 kg, what is the magnitude of the net force acting on the kayak?
vf^2=vi^2+2ad
but a= force/mass
you know vi=0 vf-.577m/s,and you know d.
solve for force.
To find the magnitude of the net force acting on the kayak, we can use Newton's second law of motion, which states that the net force (F_net) acting on an object is equal to the mass (m) of the object multiplied by its acceleration (a). Mathematically, this can be expressed as:
F_net = m * a
Given that the combined mass of the person and the kayak is 60.6 kg and the acceleration of the kayak is 0.577 m/s², we can substitute these values into the equation:
F_net = 60.6 kg * 0.577 m/s²
Calculating this, we find:
F_net = 34.97 N
Therefore, the magnitude of the net force acting on the kayak is approximately 34.97 Newtons.
To find the magnitude of the net force acting on the kayak, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration.
Given:
Initial velocity (u) = 0 m/s
Final velocity (v) = 0.577 m/s
Distance (d) = 0.565 m
Mass of person and kayak (m) = 60.6 kg
First, let's calculate the acceleration of the kayak using the kinematic equation:
v^2 = u^2 + 2ad
Rearranging the equation to solve for acceleration (a), we have:
a = (v^2 - u^2) / (2d)
Plugging in the values, we get:
a = (0.577^2 - 0^2) / (2 * 0.565)
a = 0.333 / 1.13
a ≈ 0.294 m/s^2 (rounded to three decimal places)
Now, we can use Newton's second law of motion:
F = ma
Plugging in the values, we get:
F = 60.6 kg * 0.294 m/s^2
F ≈ 17.8356 N (rounded to four decimal places)
Therefore, the magnitude of the net force acting on the kayak is approximately 17.836 N.
F=ma
we know m but don't know the a .
So lets find the a first.
V(final)^2 = V(initial)^2+2d
so a = V(final)^2/2d
a=0.295
now F=ma
F= 60.6*0.295
=17.851 N