How many carbon atoms are contained within 10.0 pounds of sugar, (sucrose) which has the formula c12h22o11?
Well, let's calculate it with a sprinkle of humor, shall we? The molecular formula of sucrose (C12H22O11) tells us that there are 12 carbon (C) atoms present. So, using a touch of clown magic, we multiply 12 by the given 10.0 pounds of sugar and end up with... *drum roll*... 120 carbon atoms! That's enough carbon atoms for a small carbon party! Just make sure to bring some snacks!
To determine the number of carbon atoms in 10.0 pounds of sucrose (C12H22O11), we need to use Avogadro's number and the molecular formula.
1. Convert the weight from pounds to grams:
10.0 pounds = 4535.92 grams (1 pound = 453.592 grams)
2. Calculate the molar mass of sucrose:
C12H22O11 has 12 carbon atoms, 22 hydrogen atoms, and 11 oxygen atoms.
The atomic masses are:
C (carbon) = 12.01 g/mol
H (hydrogen) = 1.01 g/mol
O (oxygen) = 16.00 g/mol
Multiply the number of atoms by their respective atomic masses and sum up the results:
(12 carbon atoms × 12.01 g/mol) + (22 hydrogen atoms × 1.01 g/mol) + (11 oxygen atoms × 16.00 g/mol) = 342.34 g/mol
3. Use Avogadro's number to find the number of moles:
Number of moles = Mass / Molar mass
Number of moles = 4535.92 g / 342.34 g/mol = 13.25 mol
4. Determine the number of carbon atoms in the given amount of sucrose:
One mole of sucrose contains 12 moles of carbon atoms (according to the molecular formula).
Therefore, the number of carbon atoms in 13.25 mol of sucrose is:
13.25 mol × 12 mol C/mol = 159 mol C
However, mole values are not whole numbers, so we should round the answer to the nearest whole number.
Thus, there are about 159 carbon atoms contained within 10.0 pounds of sucrose.
To determine how many carbon atoms are present in 10.0 pounds of sucrose, we need to use some basic concepts from chemistry and convert the given information into a measurable unit.
1. Determine the molar mass of sucrose:
The molar mass of sucrose (C12H22O11) can be calculated by summing up the atomic masses of each element present in it. The atomic masses of carbon (C), hydrogen (H), and oxygen (O) are 12.01 g/mol, 1.01 g/mol, and 16.00 g/mol, respectively.
12 * 12.01 g/mol = 144.12 g/mol (carbon)
22 * 1.01 g/mol = 22.22 g/mol (hydrogen)
11 * 16.00 g/mol = 176.00 g/mol (oxygen)
So, the molar mass of sucrose is:
144.12 g/mol + 22.22 g/mol + 176.00 g/mol = 342.34 g/mol
2. Convert pounds to grams:
Since the molar mass of sucrose is in grams per mole, we need to convert 10.0 pounds into grams. 1 pound is approximately equal to 453.592 grams. Therefore:
10.0 pounds * 453.592 g/pound = 4535.92 grams
3. Calculate the moles of sucrose:
By dividing the given mass (in grams) by the molar mass of sucrose, we can determine the number of moles.
Number of moles = Mass (g) / Molar mass (g/mol)
Number of moles = 4535.92 g / 342.34 g/mol ≈ 13.26 moles
4. Find the number of carbon atoms:
The formula C12H22O11 indicates that there are 12 carbon atoms in each molecule of sucrose (C12). Therefore, to determine the total number of carbon atoms, we can multiply the number of moles by Avogadro's number (6.022 × 10^23 atoms/mol) and then multiply it by the number of carbon atoms (12).
Total number of carbon atoms = Number of moles × Avogadro's number × Number of carbon atoms
Total number of carbon atoms = 13.26 moles × 6.022 × 10^23 atoms/mol × 12 atoms = 9.591 × 10^25 atoms
Therefore, there are approximately 9.591 × 10^25 carbon atoms in 10.0 pounds of sucrose.
10 lbs x (453.6 g/lb) = ? g sugar
How many mols sugar is that. ?g sugar/molar mass sugar = mols sugar.
In ONE (1) mols sugar there are 6.022E23 molecules.
There are 6 atoms C in ONE (1) molecule sugar.