Find the pressure exerted by a waterbed with dimensions of 2 m x 2 m which is 30 cm thick. (hint: use density of water)

To find the pressure exerted by the waterbed, we can use the formula for pressure which is defined as force per unit area.

First, let's calculate the force exerted by the waterbed. The force is equal to the weight of the water contained within the bed.

To find the weight, we need to know the volume of water in the bed. The volume is equal to the area of the bed multiplied by its thickness:

Volume = Area × Thickness

Given that the dimensions of the waterbed are 2 m x 2 m and it is 30 cm thick, we need to convert the thickness to meters:

Thickness = 30 cm = 0.3 m

Now we can calculate the volume of water:

Volume = 2 m × 2 m × 0.3 m = 1.2 m^3

Next, we need to calculate the weight of the water. The weight is equal to the mass of the water multiplied by the acceleration due to gravity (g), and the mass is equal to the density of water multiplied by the volume:

Density of water = 1000 kg/m^3 (approximate value)

Weight = Density × Volume × g

where g is the acceleration due to gravity, which is approximately 9.8 m/s^2.

Weight = 1000 kg/m^3 × 1.2 m^3 × 9.8 m/s^2 = 11,760 N

Now that we have found the force exerted by the waterbed, we can calculate the pressure.

Pressure = Force / Area

The area of the bed is 2 m × 2 m = 4 m^2.

Pressure = 11,760 N / 4 m^2 = 2,940 Pa (Pascal)

Therefore, the pressure exerted by the waterbed is 2,940 Pascal.