How much energy(in calories)would it take to heat 13g of water 2 degrees Celsius??
1.00cal/1g C = 13 x 2 = 26 Calories
Is that right?
Answer is correct!
Q=mcΔT
However, use of the equality sign is valid only when both sides of the sign are equivalent.
You could write:
Energy required
=13g * 1.00 cal/g°C * 2 °C
=26 cal
Thank you
No, the calculation you provided is incorrect. To determine the amount of energy required to heat water, you need to use the specific heat capacity of water, which is approximately 1 calorie per gram per degree Celsius (1 cal/g°C).
The correct calculation would be:
Energy = mass x specific heat x temperature change
In this case:
Mass of water = 13g
Temperature change = 2°C
Specific heat of water = 1 cal/g°C
Energy = 13g x 1 cal/g°C x 2°C
Energy = 26 calories
So, the correct answer is that it would take 26 calories of energy to heat 13g of water by 2 degrees Celsius.