Can anyone explain this equation.
Simplify by removing factors of 1.
q^2-64/(q+8)^2
I don't know what you mean by "factors of one", but the numerator can be written (q+8)(q-8), so you can do some cancelling of q+8 terms in numerator and denominator. You will end up with (q-8)/(q+8)
thanks
To simplify the given equation, we need to remove factors of 1.
The equation you provided is:
q^2 - 64 / (q + 8)^2
To remove factors of 1, we can start by factoring both the numerator and denominator of the fraction.
The numerator, q^2 - 64, can be factored as the difference of squares. Remember, the difference of squares identity is:
a^2 - b^2 = (a + b)(a - b)
Applying this identity, we have:
q^2 - 64 = (q + 8)(q - 8)
Now let's observe the factor in the denominator, which is (q + 8)^2. This means it is being multiplied by itself:
(q + 8)(q + 8)
To simplify the equation further, we can cancel out the common factor (q + 8) in both the numerator and denominator:
(q + 8)(q - 8) / (q + 8)(q + 8)
Note that the (q + 8) factor cancels out, leaving us with:
q - 8 / (q + 8)
So, after simplifying by removing factors of 1, the equation becomes q - 8 / (q + 8).