a C4H8(g)+â O2(g)⟶ ã CO2(g)+ä H2O(g)
balance this equation put a coefficient in a,b,y,d to balance equation please help
Let me show you in steps how to do this. It's too simple to let it get to you.
C4H8(g) + O2(g)⟶ CO2(g) + H2O(g)
Look at C4H8 so YOU KNOW CO2 must be at least 4 so place a 4 there.
C4H8(g) + O2(g)⟶ 4CO2(g) + H2O(g)
Look at the H so YOU KNOW H2O on the right must be at least 4. Place a 4 there.
C4H8(g) + O2(g)⟶ 4CO2(g) + 4H2O(g)
Step 3.
You have the C4H8 taken care of and it leaves only O2 on the left. So you count up on the RIGHT the number of O atoms. There are 8 from CO2 and 4 from H2O to make a total of 12. That means a 6 for O2.
C4H8(g) + 6O2(g)⟶ 4CO2(g) + 4H2O(g)
:-)
a=1
b=6
y=4
d=4
omg thank you !!!! u dk how long it took me to figure this out :)
To balance the equation C4H8(g) + O2(g) -> CO2(g) + H2O(g), you can follow the steps below:
Step 1: Count the number of atoms for each element on both sides of the equation.
C: 4 on the left, 1 on the right
H: 8 on the left, 2 on the right
O: 2 on the left, 3 on the right
Step 2: Start with the element that appears in the fewest places. In this case, it is carbon (C).
Step 3: To achieve an equal number of carbon atoms on both sides, you need to put a coefficient in front of CO2 on the right side. Let's put an "a" in front of CO2.
C4H8(g) + O2(g) -> a CO2(g) + H2O(g)
Now, we have:
C: 4 on the left, a on the right
H: 8 on the left, 2 on the right
O: 2 on the left, 3 on the right
Step 4: Look at the next element that appears in an unbalanced manner. In this case, it is hydrogen (H).
Step 5: To equalize the number of hydrogen atoms, you need to put a coefficient in front of H2O on the right side. Let's put a "b" in front of H2O.
C4H8(g) + O2(g) -> a CO2(g) + b H2O(g)
Now, we have:
C: 4 on the left, a on the right
H: 8 on the left, 2b on the right
O: 2 on the left, 3b on the right
Step 6: Now, let's balance the oxygen (O) atoms.
On the left side, there are 2 oxygen atoms from the O2.
On the right side, there are a CO2 and b H2O, which contribute to a total of (1 x 2) + (b x 1) = 2 + b oxygen atoms.
To balance the equation, we need to make the number of oxygen atoms the same on both sides. So, b should be 1.
C4H8(g) + O2(g) -> a CO2(g) + H2O(g)
Now, we have:
C: 4 on the left, a on the right
H: 8 on the left, 2 on the right
O: 2 on the left, 2 on the right
As a result, the balanced equation is:
C4H8(g) + 6O2(g) -> 4CO2(g) + 4H2O(g)