2) A single slit diffraction pattern is created using light of wavelength 700nm and a slit which is 0.020mm wide.
a) What is the angular width of the central diffraction bright region?
b) How wide is the central bright region observed on a screen located 20cm from the slit?
Use the website reference provided in my previous answer about diffraction around a wire.
To find the angular width of the central diffraction bright region, we can use the formula:
θ = λ / w
where:
θ is the angular width of the central bright region,
λ is the wavelength of light, and
w is the width of the slit.
a) Given that the wavelength (λ) is 700nm = 700 x 10^(-9)m, and the slit width (w) is 0.020mm = 0.020 x 10^(-3)m, we can calculate the angular width (θ) using the formula:
θ = (700 x 10^(-9)m) / (0.020 x 10^(-3)m)
= 35 x 10^(-6) radians
Therefore, the angular width of the central diffraction bright region is 35 x 10^(-6) radians.
b) To find the width of the central bright region observed on a screen located 20cm from the slit, we can use the formula:
y = L x tan(θ)
where:
y is the width of the central bright region,
L is the distance from the slit to the screen, and
θ is the angular width of the central bright region.
Given that L is 20cm = 0.20m, and θ is 35 x 10^(-6) radians, we can calculate the width of the central bright region (y) using the formula:
y = (0.20m) x tan(35 x 10^(-6) radians)
Therefore, the width of the central bright region observed on a screen located 20cm from the slit can be calculated using the given values.