Need help on this problem please...
What is the distance between P(–4, 3) and Q(6, 1)? Round to the nearest tenth.
You will have to use the distance formula. Do you know what the formula is?
Yes, thank you.
Is it the square root of 14?
No it shouldnt be that small
To find the distance between two points in a coordinate plane, you can use the distance formula. The distance formula is derived from the Pythagorean theorem and can be used to calculate the distance between any two points (x1, y1) and (x2, y2) in a coordinate plane.
The distance formula is given by:
d = √[(x2 - x1)² + (y2 - y1)²]
Let's apply this formula to find the distance between P(–4, 3) and Q(6, 1).
Step 1: Identify the coordinates of point P and Q.
P = (x1, y1) = (–4, 3)
Q = (x2, y2) = (6, 1)
Step 2: Use the distance formula to calculate the distance.
d = √[(6 - (-4))² + (1 - 3)²]
= √[(6 + 4)² + (-2)²]
= √[10² + 4]
= √[100 + 4]
= √104
≈ 10.2 (rounded to the nearest tenth)
Therefore, the distance between P(–4, 3) and Q(6, 1) is approximately 10.2 units when rounded to the nearest tenth.