Can someone help me with this? Thanks!
Find the zeros of the function algebraically. f(x)=x^2-8x+15
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10x
xeroes will be when the numberator is zero.
x^2-8x+15=0
(x-5)(x-3)=0
xeroes at 3,and 5
@bobpursley
How did you get 3 and 5?
Of course! I can help you with that.
To find the zeros of a function algebraically, we need to set the function equal to zero and solve for the values of x.
In this case, we have the function f(x) = (x^2 - 8x + 15) / (10x).
To find the zeros, we need to solve the equation: (x^2 - 8x + 15) / (10x) = 0.
To eliminate the fraction, we can multiply both sides of the equation by 10x, resulting in the equation x^2 - 8x + 15 = 0.
This is now a quadratic equation, which can be factored or solved using the quadratic formula. In this case, the equation can be factored as (x - 3)(x - 5) = 0.
Now, we can set each factor equal to zero and solve for x:
x - 3 = 0 or x - 5 = 0
When we solve these linear equations, we find:
x = 3 or x = 5
Therefore, the zeros of the function f(x) = (x^2 - 8x + 15) / (10x) are x = 3 and x = 5.