I need to know how to work this problem:

A 12-ft-by-15-ft rectangular swimming pool has a 3-ft-wide no-slip surface around it. What is the outer perimeter of the no-slip surface?
78 ft
78 ft2
198 ft
198 ft2

DOES ANYONE HAVE THE FULL TEST

Add 6 feet to each of the dimensions.

18 by 21 = 78 feet

To find the outer perimeter of the no-slip surface around the rectangular swimming pool, we need to calculate the sum of all four sides of the no-slip surface.

First, let's find the dimensions of the no-slip surface by subtracting 3 feet from each side of the pool.

The length of the pool with the no-slip surface is (12 ft - 2 * 3 ft) = 6 ft,
and the width of the pool with the no-slip surface is (15 ft - 2 * 3 ft) = 9 ft.

Now that we have the dimensions of the no-slip surface, we can calculate its perimeter by adding all four sides:

Perimeter = 2 * length + 2 * width
Perimeter = 2 * 6 ft + 2 * 9 ft
Perimeter = 12 ft + 18 ft
Perimeter = 30 ft

Therefore, the outer perimeter of the no-slip surface is 30 ft.

I'll get my answers up here when I finish.