A sphere with a charge of 1.5 x 10-6 C experiences a force of 3.5 x 102 N when it is located at a certain point in an electric field. Determine the magnitude of the electric field intensity at this location. (remember E = Fon q' / q', and 1 µC = 1.00 x 10-6 C

To determine the magnitude of the electric field intensity at the given location, we can use the formula:

E = F / q'

Where:
E is the electric field intensity,
F is the force experienced by the sphere, and
q' is the charge of the sphere.

Given:
F = 3.5 x 10^2 N (force experienced by the sphere)
q' = 1.5 x 10^-6 C (charge of the sphere)

Substituting these values into the formula, we have:

E = (3.5 x 10^2 N) / (1.5 x 10^-6 C)

Now, we can simplify the expression:

E = (3.5 x 10^2 N) * (1 / (1.5 x 10^-6 C))

To simplify further, we divide the numerator and denominator by 1.5 x 10^-6 C:

E = (3.5 x 10^2 N) * (1 / (1.5 x 10^-6 C)) * (1.5 x 10^-6 C / 1.5 x 10^-6 C)
E = (3.5 x 10^2 N) * (1.5 x 10^-6 C / 1.5 x 10^-6 C)

Now, we can multiply the numbers:

E = (3.5 x 1.5) x (10^2 x 10^-6 C / 10^-6 C)
E = 5.25 x 10^-4 N/C

Therefore, the magnitude of the electric field intensity at the given location is 5.25 x 10^-4 N/C.