How much benzoic acid is still dissolved when 73.53 mL of saturated boiling water is cooled to 20oC. The solubility at 20oC is 0.029g/10mL.
The solubility is 0.029g/10 mL or 0.0029g/1 mL so there will be 73.53 times that in 73.53 mL. right?
To calculate the amount of benzoic acid that is still dissolved when the saturated boiling water is cooled to 20oC, we need to determine the amount of benzoic acid that precipitates out of the solution as it cools.
First, let's calculate the amount of benzoic acid that is initially dissolved in 73.53 mL of saturated boiling water.
Since the solubility of benzoic acid at 20oC is given as 0.029g/10mL, we can calculate the amount of benzoic acid dissolved in 73.53 mL as follows:
Amount of benzoic acid initially dissolved = (0.029g/10mL) x (73.53 mL / 10 mL)
Simplifying the expression:
Amount of benzoic acid initially dissolved = 0.029g x 7.353
Amount of benzoic acid initially dissolved = 0.213537 g
Now, we need to calculate the solubility of benzoic acid at 20oC in the cooled solution. Since we've determined that 0.213537 g of benzoic acid was initially dissolved, we subtract this value from the total solubility at 20oC to find the remaining amount of benzoic acid in the solution:
Amount of benzoic acid remaining = Total solubility at 20oC - Amount of benzoic acid initially dissolved
Amount of benzoic acid remaining = 0.029g - 0.213537g
Amount of benzoic acid remaining = -0.184537 g
However, it is not possible for the amount of benzoic acid remaining to be negative. This indicates that all the benzoic acid has precipitated out of the solution as it cooled to 20oC, and there is no benzoic acid left dissolved in the solution.