If a car can go from 0 to 60mi/hr in 8.0 seconds, what would be its final speed after 5.0 seconds if its starting speed were 50mi/hr? don't know what equation to use. please help
assuming constant acceleration, then since the velocity changed by 88ft/s in 8 seconds,
a = 11 ft/s^2
Now to find v, just recall that
v(t) = Vo + at
Just plug in your numbers.
Of course, in the real world, acceleration from a standing start is very different from a starting speed of 50 mph!
To solve this problem, you can use the equation for constant acceleration:
v = u + at
Where:
v = final velocity
u = initial velocity
a = acceleration
t = time
In this case, the acceleration is the rate at which the car's speed increases from 0 to 60 mph in 8.0 seconds. To find the acceleration, you can use the equation:
a = (v - u) / t
Given:
Initial velocity (u) = 0 mph
Final velocity (v) = 60 mph
Time (t) = 8.0 seconds
Substituting the values into the acceleration equation:
a = (60 mph - 0 mph) / 8.0 s
a = 60 mph / 8.0 s
a = 7.5 mph/s
Now that you have the acceleration, you can find the final velocity after 5.0 seconds using the equation:
v = u + at
Given:
Initial velocity (u) = 50 mph
Acceleration (a) = 7.5 mph/s
Time (t) = 5.0 seconds
Substituting the values into the equation:
v = 50 mph + 7.5 mph/s * 5.0 s
v = 50 mph + 37.5 mph
v = 87.5 mph
Therefore, the final speed of the car after 5.0 seconds, with an initial speed of 50 mph, would be 87.5 mph.